Example
Return the year part of the specified date:
sql
SELECT DatePart("yyyy", #09/05/2017#);
Definition and Usage
The DatePart() function returns a specified part of a date, as an integer.
Syntax
text
DatePart(datepart, date, firstdayofweek,
firstweekofyear)
Parameter Values
| Parameter | Description |
|---|---|
| datepart | Required. The date part to return. Can be one of the following values: yyyy = Year q = Quarter m = month y = Day of the year d = Day w = Weekday ww = Week h = hour n = Minute s = Second |
| date | Required. The date value to be evaluated |
| firstdayofweek | Optional. Specifies the first day of the week. Can be one of the following values: 0 = Use the NLS API setting 1 = Sunday (default) 2 = Monday 3 = Tuesday 4 = Wednesday 5 = Thursday 6 = Friday 7 = Saturday |
| firstdayofyear | Optional. Specifies the first week of the year. Can be one of the following values: 0 = Use the NLS API setting 1 = Use the first week that includes Jan 1st (default) 2 = Use the first week in the year that has at least 4 days 3 = Use the first full week of the year |
Technical Details
| Works in: | From Access 2000 |
|---|
More Examples
Example
Return the month part of the specified date:
sql
SELECT DatePart("m", #09/05/2017#);
Example
Return the weekday of today's date:
sql
SELECT DatePart("w", Date());